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igor_vitrenko [27]
3 years ago
11

The drawing shows a stack of alternating cups. The cups are 9.2 cm high. How many cups will fit in a door that is 211.77 cm high

?
Mathematics
1 answer:
KIM [24]3 years ago
7 0

Answer:

The total number of whole cups that we can fit in the dispenser is 25

Step-by-step explanation:

It is given that the height of each cup is 20 cm.

But when we stack them one on top of the other, they only add a height of 0.8 to the stack.  

The stack of cups has to be put in a dispenser of height 30 cm.

So we need o find out how many cups can fit in the dispenser.

Since the first cup is 20 cm high, the height cannot be reduced. So the space to fit in the remaining cups in the stack is only 30-20 cm as that’s the remaining space in the dispenser

So,

30 - 20 = 10 cm

To stack the other cups we have 10 cm of height remaining

As we know that addition of each adds 0.8 cm to the stack, the total number of cups that can be fit in the dispenser can be calculated by the following equation. Let the number of cups other than the first cup be denoted by ‘x’.

10 + 0.8x = 30

0.8x = 20

x = 25

The total number of cups that we can fit in dispenser is 25

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What two numbers when added equal 25 and when multiplied = -200
Igoryamba
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WILL MAKE BRAINLIEST!!! A Ferris wheel has a diameter of 220 feet and the center of the wheel is 125 feet above the ground. The
daser333 [38]
Since the radius of a circle is half its diameter, the radius of our Ferris wheel is r= \frac{220}{2} =110ft

Next, we are going to convert from revolutions per minute to degrees per second.
We know that t<span>he wheel makes a complete turn every 2 minutes, so it makes a complete turn in 120 seconds. Since there are 360° in a complete turn, we can set up our conversion factor:
</span>\frac{1*360}{120}=3 degrees per second 
<span>
Now, lets find the height:
</span>We know that <span>the passenger is at the lowest point on the wheel when t=0; since the wheel is 125 feet above the ground, at t=0 h=125. To find t at the top, we are going to take advantage of the fact that the wheel will turn 180° from the lowest point to the top and that it turns 3° every second:
</span>t= \frac{180}{3}
t=60
Notice that the height at the top is the diameter of the wheel plus the height above the ground, so h=220+125=345.

To model the situation we are going to use the cosine function, but notice that cos (\alpha) is 1 when \alpha =0 and -1 wen \alpha =180. Since we want the opposite, we are going to use negative cosine.
Notice that we want \alpha =180 when t=60, so we are going to use -cos(3t). Next, we are going to multiply our cosine by the radius of our wheel: -110cos(3t), and last but not least we are going to add the sum of the radius of the wheel plus the height above the ground:
h=110+125-110cos(3t)
h=225-110cos(3t)

Now that we have our height function lets check if everything is working:
<span>the passenger is at the lowest point at t=0; we also know that the lowest point is 125 feet above the ground, so lets evaluate our function at t=0:
</span>h=225-110cos(3t)
h=225-110cos(3*0)
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So far so good. 
We also know that at t=60, our passenger is 345 feet above the ground, so lets evaluate our function at t=60 and check if coincides:
h=225-110cos(3t)
h=225-110cos(3*60)
h=225-110cos(180)
h=345feet 

We can conclude that cosine function that express the height h (in feet) of a passenger on the wheel as a function of time t (in minutes) ) is: h=225-110cos(3t)
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AveGali [126]

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