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Flura [38]
3 years ago
8

In a race, Jason's position was -11 1/5 feet relative to the leader after 1 3/4 minutes. On average, how much did Jason's positi

on relative to the leader change per minute?
Respond with your answer as a mixed number in simplified form.
Mathematics
2 answers:
vivado [14]3 years ago
7 0

Answer:

0 feet moved

Step-by-step explanation:


iragen [17]3 years ago
3 0

Answer:

it is 0 feet moved


Step-by-step explanation:


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The volume of this cylinder is 20,403.72 cubic yards. What is the radius? Use ​ ≈ 3.14 and round your answer to the nearest hund
MakcuM [25]
The formula for the volume of a cylinder is V=3.14r^2(h).
So substituting the volume: 20,403.72=3.14r^2(h).

To solve for ‘r’, divide both sides by 3.14h
r^2=6,498/h
Then find square root of both sides
r= sqrt(6,498/h)
Since ‘h’ is not specified here, it cannot be solved further.
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2 years ago
Pleaseeeeee help I’m so confused
SSSSS [86.1K]

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4747

Step-by-step explanation:

8 0
3 years ago
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Solve this 2-step Equation <br> 5=4a-7
katen-ka-za [31]

Answer:

a=3

Step-by-step explanation:

5=4a-7

add 7 on both sides

5+7=4a(-7+7)

12=4a

Now divide 4 on both sides

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3 years ago
EThe graph of a quadratic function passes through the points (6,0) and (p,0). The maximum point
MA_775_DIABLO [31]

Answer:

p = - 5

Step-by-step explanation:

The vertex of the function is (0.5, 30.25 )

Since the roots are (6, 0) and (p, 0) then the axis of symmetry is vertical

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The axis of symmetry passes through the midpoint of the roots, thus

\frac{6+p}{2} = 0.5 ( multiply both sides by 2 )

6 + p = 1 ( subtract 6 from both sides )

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6 0
3 years ago
Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)
ElenaW [278]

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

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1 year ago
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