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Bogdan [553]
2 years ago
5

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

Mathematics
2 answers:
melisa1 [442]2 years ago
8 0
Y= -1/3x + 2

Important takeaway is that the slopes of two perpendicular lines are always negative reciprocals.
ElenaW [278]2 years ago
3 0

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

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5 0
3 years ago
Find the slope please
zavuch27 [327]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find the slope of this graph; we are provided with two points:

\star~\mathrm{(6,0)}

\star~\mathrm{(0,-5)}

\triangle~\fbox{\bf{KEY:}}

  • What we need in order to find the slope are two points and the slope formula.

Here's the formula:

\star~\boxed{\mathrm{\cfrac{y2-y1}{x2-x1}}}

Where

y2 and y1 are y-coordinates

x2 and x1 are x-coordinates

Substitute the values:

\star~\mathrm{\cfrac{-5-0}{0-6}}}

Simplify!

\star~\mathrm{\cfrac{-5}{-6}}}

Simplify more!

\star~\mathrm{\cfrac{5}{6}}

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0
2 years ago
3.25 x 10^4 as an ordinary number
luda_lava [24]

Answer:

32500

Step-by-step explanation:

3.25 x 10^4

3.25 x 10000

Move the decimal point 4 places to the right.

32500

6 0
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