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Bogdan [553]
1 year ago
5

Write the equation of a line that is perpendicular to y=3x-2 that passes trough the point (-9,5)

Mathematics
2 answers:
melisa1 [442]1 year ago
8 0
Y= -1/3x + 2

Important takeaway is that the slopes of two perpendicular lines are always negative reciprocals.
ElenaW [278]1 year ago
3 0

\huge\boxed{y-5&=-\frac{1}{3}(x+9)}

First, we'll find the slope of the new line. The first line has a slope of 3. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by -1) to get -\frac{1}{3} for the new slope.

Then, we'll use the point-slope form to make the new equation, where m is the slope and (x_1,y_1) is a point on the line:

\begin{aligned}y-y_1&=m(x-x_1)\\y-5&=-\frac{1}{3}(x-(-9))\\y-5&=-\frac{1}{3}(x+9)\end{aligned}

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