The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively
<h3>The value of P(A)</h3>
The event A is given as:
A : Sum greater than 6
In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes
This means that:
P(A) = 21/36
Simplify
P(A) = 7/12
<h3>The value of P(B)</h3>
The event B is given as:
B : Sum is divisible by 2
In the sample space of a roll of two dice, there are 18 outcomes that are divisible by 2, out of a total of 36 outcomes
This means that:
P(B) = 18/36
Simplify
P(B) = 1/2
Hence, the probability values of P(A) and P(B) are 7/12 and 1/2, respectively
Read more about probability at:
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Answer: 3hours
Explanation: it would take 3hours because 45 divided by 3 is 15, and also 15 x 3 is 45.
Hope that helps, have a good day :)
Answer:
x = 6
Step-by-step explanation:
1. set up the equation
p-7=30
2. Add 7 to bith sides to cancel the 7
p-7 (+7)= 30+7
p=37
P is equal to 37
This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20) and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.
Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710
Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710
as before.