you must substitute x in the equation given :)
examples:
when x is -2
therefore, y = 2(-2) + 3
y = -1
when x is 0
therefore, y = 2(0) + 3
y = 3
when x is 1
therefore, y = 2(1) + 3
y = 5
when x is 3
therefore, y = 2(3) + 3
y = 9
for (b) you only have to plot based on the table ;)
hope this helps
Obviously, it's not rational, because it's the sum of two square roots, so cancel out A and B right away.
If we solve it
sqrt (18) + sqrt (2)
= sqrt (9*2) + sqrt (2)
= 3 sqrt (2) + sqrt (2)
= 4 sqrt (2)
D :D
Answer:
1. The negative sign on an exponent means the reciprocal. A negative exponent tells how many times to divide a base number.
2. A positive tells how many times to multiply a base number.
could you also give me a brainliest if I am correct.
thanks!
Answer:
a. Chi-square test of independence
Step-by-step explanation:
The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.
In the given problem the Equal , more or less are the attributes.
The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
They'll be able to get 34 bottles from the containers.
Step-by-step explanation:
Since the bottles are cylindrical we can calculate their volume by using the following formula:
V = base_area*h
V = \pi*(r^2)*h
r = d/2 = 4/2 = 2 inches
V = 3.14*(2^2)*5 = 3.14*4*5
V = 3.14*20 = 62.8 inches^3
In order to know how many full bottles the players will get we need to divide the total volume of the containers, which is given by the sum of the volume of each container, and divide it by the volume of each bottle. We have:
bottles = (345*pi + 345*pi)/62.8 = 690*pi/62.8 = 2,166.6/62.8 = 34.5
Since the problem wants the amount of full bottles we only take the integer part, so they will be able to get 34 bottles from the containers.