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3 years ago

What is the slope intercept form of the equation for the line provided?

Mathematics

1 answer:

OverLord2011 [107]3 years ago

3 0

Answer : B

slope = 5/8

given point is (-8,-4)

Use point slope formula

y - y1 = m (x - x1)

m = 5/8 , x1 = -8 and y1 =-4

Plug in all the values in the formula

$y - (-4) =\frac{5}{8}(x - (-8))$

$y+4 =\frac{5}{8}x + 5$

Subtract 4 on boths ides

$y=\frac{5}{8}x + 1$

So answer is option B

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Becky accepted a job as an inventory manager after being offered an $800 signing bonus. If she makes $23 an hour, which equation

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Y = 23x + 800 (Apex)

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3 years ago

Calvin bought 20 pencils at 0.45 each how many change did he get from a 10 dollar bill

ehidna [41]

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3 years ago

Read 2 more answers

Which of the following represents 3x-5y+10=0 written in slope-intercept form?

taurus [48]

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:

$3x-5y + 10 = 0$

We manipulate algebraically:

We subtract 10 from both sides of the equation:

$3x-5y = -10$

We subtract 3x from both sides of the equation:

$-5y = -3x-10$

We multiply by -1 on both sides of the equation:

$5y = 3x + 10$

We divide between 5 on both sides of the equation:

$y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2$

Thus, the equation in the slope-intercept form is $y = \frac {3} {5} x + 2$

Answer:

$y = \frac {3} {5} x + 2$

5 0

3 years ago

Need help with this please

Katarina [22]

Answer:

The third side is sqrt(77)

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

2^2 + b^2 = 9^2

4+ b^2 = 81

Subtract 4 from each side

b^2 = 81-4

b^2=77

Take the square root of each side

sqrt(b^2) = sqrt(77)

b = sqrt(77)

The third side is sqrt(77)

5 0

3 years ago

Which expression is equivalent to 5y^3 over (5y)-^2

Flura [38]

Answer:

$125y^5$

Step-by-step explanation:

$\mathrm{Factor}\:\left(5y\right)^{-2}:\quad 5^{-2}y^{-2}$

$\mathrm{Cancel\:}\frac{5y^3}{5^{-2}y^{-2}}:\quad 5^3y^5$ $=5^3y^5$

$5^3=125$

<em>Hope this helps!!!</em>

3 0

3 years ago