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2 years ago

A student must study for 20 to 30 hours a week to maintain their grade point average. If the

1 answer:

7 0

The answer would be [20/7,30/7]

That gives you an idea of how long each day the student must study in order to maintain their GPA

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Lesson 6 Homework Practice Select an Appropriate Display

Naddika [18.5K]

Can’t answer this as it gives no information?

6 0

3 years ago

Andre tried to solve the equation 1/4(x+12)=2 what was his mistake?

GarryVolchara [31]

Step-by-step explanation:

1. 1/4(x + 12)=2 - first isolate X'

- 12 -12

2. 1/4(x) = -10 - 1/4 since its a fraction, you'll have to subtract not divide

-1/4 - 1/4

3. x = -10.25

Andre did the first step correctly, but on the second step he just divided 1.4 by -10, instead of subtract 1/4 from both sides.

8 0

3 years ago

Andrea ran 4 3/8 miles on

MrRissso [65]

(4 3/8) + (5 1/3)

(4+5)(3/8 + 1/3)

9 + (17/24)

she ran 9 17/24 miles total

8 0

3 years ago

What is the area of the shaded portion of the circle?

SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A= $(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi$

Since $\frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}$ , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

$A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi$

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from $A_1$ .

The area of the triangle is given by

$A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2$

Thus the area of the shaded portion of the circle is

$A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2$

3 0

3 years ago

What is the value of (17+8)-6x2?

Marina86 [1]

The answer is 13 for your question

8 0

3 years ago