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2 years ago

A large city has a population of 8,000,000 and an area of 20.5 square miles. what is the city's approximate population density?

Mathematics

1 answer:

gayaneshka [121]2 years ago

3 0

Answer: Approximately 390,244 people per square mile

Work Shown:

Density = population/area

Density = (8 million people)/(20.5 square miles)

Density = 390,243.9024 approximately

This rounds to 390,244 since we're talking about the number of people.

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Which function represents transforming ƒ(x) = 3x with a reflection over the x-axis and a vertical shift of 4 units?

Oxana [17]

Answer:

D. $h(x)=-3x+4$

Step-by-step explanation:

we are given

$f(x)=3x$

Firstly, it is reflected over x-axis

we know that for reflection about x-axis , we can replace y as -y

we get

$g(x)=-f(x)$

$g(x)=-3x$

now, it is vertical shift up by 4 units

so, we can add 4 to y-value

we get

$h(x)=g(x)+4$

$h(x)=-3x+4$

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3 years ago

Please help me out :)

Alex17521 [72]

79-y=2y+22

Add y on both sides

79=3y+22

Subtract 22 from both sides

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Divide by 3 on both sides

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3 years ago

For the decimal 0.09, (a) write a fraction and (b) write a percent.

sp2606 [1]

Answer:

9/100, 9%

Step-by-step explanation:

0.09 is equal to 9/100

0.09 is equal to 9 percent

3 0

3 years ago

Read 2 more answers

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago

How to write 4408730 in expanded form

Vedmedyk [2.9K]

4,408,730 = 4,000,000 + 400,000 + <span>8,000 + 700 + 30 </span>

3 0

3 years ago

Read 2 more answers