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Rashid [163]
3 years ago
13

What is 0.0000091 written in scientific notation

Mathematics
2 answers:
zaharov [31]3 years ago
8 0
The goal of writing a number in scientific notation is to have a decimal number, with one digit to the left of the decimal point, followed by a <span>×⨯</span><span>1010</span> to some power. To format the number this way, multiply the <span>0.00000910.0000091</span> by <span>1010</span> <span><span>−6</span><span>-6</span></span> times, making it <span>9.19.1</span>. Each multiplication by <span>1010</span> moves the decimal point one digit to the left, but in order to keep the same number, multiply <span>9.19.1</span> by <span><span>10<span>−6</span></span><span>10<span>-6</span></span></span>.<span>9.1×<span>10<span>−<span>6</span></span></span></span>
amm18123 years ago
6 0
9.1 x 10^-6

hope that helps
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malfutka [58]
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3 years ago
Can you help? Having a hard time figuring this out. Thanks
Dmitrij [34]

Answer:

3a) The value of  x = 56

3b) The measure of ∠ H T M = 90°

3c) The radius of the circle = 53

Step-by-step explanation:

3a) ∵ A F is a tangent to the circle O at point F

∵ Secant AH intersects circle O at point T

∴ (A F)² = (A T)(A H)

∴ 7( x + 7) = (21)² ⇒ ÷ 7

∴ x + 7 = 63

∴ x = 63 - 7 = 56

3b) ∵ HM is a diameter

∴ The measure of the arc HM = 180° ⇒ semi-circle

∵ ∠ H T M is inscribed angle subtended by the arc HM

∴ m ∠ H T M = half the measure of arc HM

∴ m ∠ H T M = 180° ÷ 2 = 90°

3c) ∵ Δ H T M is a right angle triangle at T

∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem

∴ (H M)² = (90)² + (56)²

∴ (H M)² = 11236

∴ HM = \sqrt{11236} = 106

∴ OM = 106 ÷ 2 = 53

∵ OM is the radius of the circle O

∴ The radius  = 53

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Answer:

A: (-5,4)

B: (7,-2)

Step-by-step explanation:

It has to be in order start with the x-axis then the y-axis

4 0
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NemiM [27]

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Step-by-step explanation:

6 0
3 years ago
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kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
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