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3 years ago

Simplify the following expressions by distributing ( Its three questions by the way)

Mathematics

1 answer:

horrorfan [7]3 years ago

7 0

Answer:

-4w+32

-10p+40

-2g+4

Step-by-step explanation:

distribute

a negative minus a negative is a positive

<h2><em><u>xoxo, </u></em></h2><h2><em><u>your highness...</u></em></h2>

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Luc carved an ice sculpture of a dragon with wings that weighed 42 pounds when he moved it one of the wings broke of and now it

prisoha [69]

The broken wing weighed 10 pounds and 14 ounces. There are 16 ounces in a pound. I hope this helps!

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3 years ago

Lim->infinity 4n^2/n^2+10000n

dybincka [34]

<span>let P(n)=4n² / n²+10000n
when n ----------> infinity, the main rule is as follow
lim </span><span>P(n)=4n² / n²+10000n = lim </span>P(n)=4n² / n²= lim 4= 4
n ----------> infinity <span> n ----------> infinity </span><span>n ----------> infinity
finally
</span>
<span>Lim->infinity 4n^2/n^2+10000n = 4</span>

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3 years ago

Write this ratio in one other way 7/13

Ierofanga [76]

You can write this ratio in two other ways:

7 to 13

7 : 13

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3 years ago

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9. What is the distance along the x axis from order pairs -8, 6 and 4,6

Blababa [14]

Answer:

12 units

Step-by-step explanation:

got it right on edg

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3 years ago

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$