G.P.E = mgh
Weight = mg = 200N
So G.P.E = 200 * 2 = 400 Joules
This would be a funny game.
Inertia, according to first Law of Newton, means that when you throw a ball it will continue moving unless a force acts over it.
Without inertia, the ball instead of continue moving, would stop as soon as it leaves your hand or foot. You had to stay pasted to the ball unitl it reaches the desired destiny for it continue moving.
Answer:

Explanation:
Given that
Stored energy E

a)
We know that stored energy in capacitor given as

Given that



C= 0.02 F
b)
Electric filed E = 9 x 10^6 V/m
We know that
V = E .d

d=1.11 mm
We know that



This is area area of the plates.
Its a sinkhole. -----------
Answer:
The force exerted by the wood on the bullet is 399.01 N
Explanation:
Given;
mass of bullet, m = 0.0021 kg
initial velocity of the bullet, u = 497 m/s
final velocity of the bullet, v = 0
distance traveled by the bullet, S = 0.65 m
Determine the acceleration of the bullet which is the deceleration.
Apply kinematic equation;
V² = U² + 2aS
0 = 497² - (2 x 0.65)a
0 = 247009 - 1.3a
1.3a = 247009
a = 247009 / 1.3
a = 190006.92 m/s²
Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;
F = ma
F = 0.0021 x 190006.92
F = 399.01 N
Therefore, the force exerted by the wood on the bullet is 399.01 N