Let the mass of 2500 kg car be
and it's velocity be
and the mass of 1500 kg car be
and it's velocity be
.
After the bumping the mass be M and it's velocity be V.
By law of conservation of momentum we have

2500 * 5 + 1500 * 1=4000 * V
V = 14000/4000 = 7/2 = 3.5 m/s
So the velocity of the two-car train = 3.5 m/s
Answer:

Explanation:
We are given that
Diameter,d=

Radius,r=
Density,
Total number of electrons,n=39
Charge on electron =
Total charge=
Distance,s=2mm=
Mass =
Initial velocity,u=0
Final speed,v=4.5 m/s




Force,F=ma





first we make a U turn and travel towards home in t = 20 s
so the distance of home from initial position is


Now after picking up the book we travel back with speed 20 m/s
so again after t = 20 s the displacement is given as

so the net displacement is given as


so it will be displaced by total displacement 200 m
Answer:
wen you stick to mangnetits togater
Explanation: