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Elina [12.6K]
3 years ago
10

Which of the following represents a molecule? A. He B. Fe C. Cl D. H2

Physics
1 answer:
klio [65]3 years ago
6 0
The answer is CI hope i help
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Calculate the pressure when a force of 200N acts on an area of 0.05cm2<br> .
deff fn [24]

FORCE ACTING ON THE BODY , F = 200N

AREA ON WHICH THE FORCE IS ACTING , A = 0.05 CM²

= 0.05*(10⁻²)

= 0.05*10⁻² M²

TO CONVERT CM TO M * BY 10⁻²

PRESSURE = FORCE / AREA

PRESSURE = 200/0.05*10⁻⁴

= 200*10⁴/0.05

= 200*10⁴*10²/5

= 20*10⁵/5

= 4*10⁵ N/M².

HOPE THIS HELPS.

4 0
2 years ago
Practice report of resistance measurement with Wheatstone bridge
belka [17]

Answer: Hii

Explanation: I had a picture.. so i think this might help you.. I answered this question using this picture, so i thought same might go to u too.. Hv a look.. Good Luck..!!

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3 years ago
What is mummification?
Nadya [2.5K]
A process in which the skin and flesh of a corpse can be preserved
5 0
3 years ago
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13) Can two nonzero perpendicular vectors be added together so their sum is zero? Explain.
Neporo4naja [7]

In order for two vectors to add to zero, they must have the same magnitude and point in opposite directions.

Two perpendicular vectors, by definition, make a right angle with each other whereas two vectors pointing in opposite directions form a straight line.

Because of this, two perpendicular vectors with nonzero magnitudes will never add to zero.

3 0
3 years ago
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A frog hops 5m east and 2m north. What is the magnitude of the frogs total displacement in m?
TiliK225 [7]

As per the question a frog jumps 5 m towards east.

Frog again jumps 2 m north.

Let the displacement along east is denoted by vector A and the displacement towards north is denoted as vector B.

Hence magnitude of A = 5 m

           Magnitude of B = 2 m

We are asked to calculate the total displacement.

Here the angle between them is 90 degree as A is towards east and B is towards north.

As per parallelogram law of vector addition,the magnitude of total displacement [R] will be-

                            R=\sqrt{ A^{2} +B^{2}+2AB\cos\theta}

                            =\sqrt{ 5^{2}+ 2^{2}+2*5*2 cos 90}

                            =\sqrt{25+4+0} m  [cos90= 0]

                            =\sqrt{29} m

                            = 5.38516 m   [ans]

                     


7 0
3 years ago
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