All categories

3 years ago

How many valence electrons does strontium (Sr) have? 1 2 5 6

Physics

2 answers:

aleksandr82 [10.1K]3 years ago

6 0

strontium has 2 valence electrons.

Tresset [83]3 years ago

5 0

Strontium has 2 valence electrons since it is in group 2

You might be interested in

The hydraulic lift in a car repair shop has an output diameter of 30 cm and is to lift cars up to 2000 kg. determine the fluid g

leonid [27]

Given Data: Diameter 'd' = 30 cm = 0.3 m Lifting Weight 'W' = mg = 2000*9.81 N = 19,620 N Calculations: Area of the lift 'A' = pi\over4*d^2=pi\over4*0.3^2=0.07 m^2

Thank you for posting your question here at brainly. I hope the answer helps.

4 0

3 years ago

Read 2 more answers

O prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to

Ira Lisetskai [31]

To calculate for the pressure of the system, we need an equation that would relate the number of moles (n), pressure (P), and temperature (T) with volume (V). There are a number of equations that would relate these values however most are very complex equations. For simplification, we assume the gas is an ideal gas. So, we use PV = nRT.

PV = nRT where R is the universal gas constant
P = nRT / V

P = 3.40 mol ( 0.08205 L-atm / mol-K ) (251 + 273.15 K) / 1.75 L

P = 83.56 atm

Therefore, the pressure of the gas at the given conditions of volume and temperature would be 83.56.

7 0

3 years ago

a bird is flying due east, it distance from a tall building is given by x(t) = 28m +(12.4m/s)t + (0.045 m/s^3)t^3. what is the i

lana66690 [7]

The instantaneous velocity is how the position is changing with respect to time in a specific point in time, as opposed to the average value given by Delta(x)/Delta(t). It's given by taking a limit of Delta(x)/Delta(t) where t approaches 0, that is, by derivating x(t) in respect to t.

v(t) = x'(t) = (28 + 12.4t + 0.045t^3)' = 12.4 + 0.135t^2

But we want to find the velocity at t = 8s:

v(8) = 12.4 + 0.135*(8)^2 = 21.04m/s

5 0

3 years ago

What must a system owner do, once the threshold leak rate has been exceeded on any low-pressure system using an ozone-depleting

soldier1979 [14.2K]

Answer:

A procedure according to the norms.

Explanation:

If possible, proceed to fix the leak in no more than 30 days from the moment it was discovered.

Otherwise, during the first 30 days develop a planification to backfit the leak or, if needed, retire the appliance. This should be executed within one year.

7 0

3 years ago

Pleaseeeee help me with b, c, and d. There are no angles.

taurus [48]

Answer:

a. 150 J

b. 150 J

c. 0 J

d. 0 J

Explanation:

The given parameters are;

The horizontal force with which the man pulls the canister, F = 50 N

The distance he moves the vacuum cleaner, d = 3.0 m

a. Work done, W = Force applied, F × Distance moved by the force, d

Therefore, for the work done by the 50 N force on the canister, we have;

W = 50 N × 3.0 m = 150 N·m = 150 J

b. Given that he pulls the canister at a constant speed, we have;

The acceleration of the canister, a = 0 m/s²

Therefore, the net force on the canister, $F_{NET}$ = F - $F_{Friction}$ = m × a

Where;

m = The mass of the canister

a = The acceleration of the canister

F = The applied force = 50 N

$F_{Friction}$ = The force of friction

∴ $F_{NET}$ = m × a = m × 0 m/s² = 0 N

Therefore;

$F_{NET}$ = F - $F_{Friction}$ = 0 N

From which we have;

F = $F_{Friction}$ = 50 N (The applied force, F is equal to the force of friction,

The work done by friction = The force of friction × The distance in which the force of friction acts

∴ The work done by friction = $F_{Friction}$ × d - 50 N × 3.0 m = 150 J

The work done by friction = 150 J

c. The normal force, N acts perpendicular to the force of friction

The distance the canister moves in the perpendicular direction, $d_p$ = 0 m

∴ The work done by the normal direction = N × $d_p$ = N × 0 m = 0 J

The work done by the normal direction = 0 J

d. The vacuum weight, W, acts on the same line as the normal force but in the opposite direction to the normal force, N

Therefore, the weight, W, acts perpendicular to the line of motion of canister

The distance the canister moves in the direction of the weight, $d_{wieght}$ = 0 m

Therefore, the work done by the weight = W × $d_{wieght}$ = W × 0 m = 0 J

The work done by the weight = 0 J

7 0

3 years ago