A system is contained by its boundary; therefore, the size of a system is limited by its boundary.
Answer:
v = 1.08 m/s
Explanation:
What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?
The decrease in PE is
d = 80.0cm * 1 / 1000m = 0.80m
h = 0.80 m /2 = 0.40 m
ΔPE = m*g*h
ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m
ΔPE = 0.1176 J
The moment of inertia of the assembly is
I = 1/12*m*L² + (m1 + m2)*(L/2)²
I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²
I = 0.032 kg·m²
KE = ½Iω²
0.1176 J = ½ * 0.032kg·m² * ω²
ω = 2.71 rad/s
v = ωr = 2.71 rad/s * 0.400m
The linear velocity
v = 1.08 m/s
Forces always work in the direction of their application.
Eg- Gravitational forces acts downwards due to the earth's pull.
The largest possible displacement you can get by combining the two of them is if they're both in the SAME direction. You walk 3 meters, stop for a breath, then walk another 4 meters in the same direction as the first one. The resultant is 7 meters.
The smallest possible resultant is 1 meter, if the two displacements are in OPPOSITE directions. This time, you walk 4 meters, stop for a breath, then you TURN AROUND and walk 3 meters back in the direction you came from. You end up 1 meter from where you started.
