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-Dominant- [34]

3 years ago

12

What is the volume of one cube with 1/2 inch sides

1 answer:

Anit [1.1K]3 years ago

8 0

Answer:

0.125 cubic inches

Step-by-step explanation:

The volume of a cube is just the length of a side length cubed. 0.5^3=0.125 in^3. Hope this helps!

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A 13ft board is to be cut into three pieces, two equal length ones and the third 9in shorter than each of the other two. If cutt

vaieri [72.5K]

Answer:

The pieces are 55 inches, 55 inches and 46 inches long

Step-by-step explanation:

A 13ft board is to be cut into three pieces consisting of two equal length ones. The third one is 9in shorter than each of the other two.

Let us first convert the length of the board to inches:

1 ft = 12 inches

13 ft = 12 * 13 = 156 inches

Let the length of each of the other two pieces be x.

Therefore, the length of the third piece is (x - 9)

Therefore, the sum of the lengths of the three pieces is equal to 156 inches. This means that:

x + x + (x - 9) = 156

x + x + x - 9 = 156

=> 3x = 156 + 9

3x = 165

x = 165 / 3 = 55 inches

Each of the first two pieces are 55 inches long.

The length of the third piece will be:

55 - 9 = 46 inches

The pieces are 55 inches, 55 inches and 46 inches long.

4 0

2 years ago

Find GH. What does GH equal?

igor_vitrenko [27]

Answer: GH = HJ = 4.6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

PLZZZZZZZ I need help i will mark brainlest

bekas [8.4K]

ANSWER

My answer is in the photo above

7 0

2 years ago

How many real solutions will y=x^2 and y=-2x have? what are the solutions?

kogti [31]

Answer:

there is none

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$

$f'(x)=12x^2+26x-12$

$f''(x)=24x+26$

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here: x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

$24(-2.6)+25$

$-37.5$

So we have a maximum at x=-2.6.

$24(.4)+25$

$9.6+25$

$34.6$

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

$y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56$

I'm shoving this into a calculator:

$y=-58.4654411$

So the approximate relative minimum is (0.4,-58.5).

If you graph $y=4x^3+13x^2-12x-56$ you should see the graph taking a dip at this point.

3 0

3 years ago