The rate of change is 16.8 million tons per year
<em><u>Solution:</u></em>
Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons
<em><u>The average rate of change is given by formula:</u></em>
Value in 1950 = 12 million tons
Value in 1955 = 96 million tons
Change in value = value in 1955 - value in 1950
Change in value = 96 million - 12 million = 84 million tons
Number of years = 1950 to 1955 = 5 years
<em><u>Substitute the given values in formula,</u></em>
<em><u></u></em>
<em><u></u></em>
Thus rate of change is 16.8 million tons per year
Answer:
0
Step-by-step explanation:
Multiplying the first equation by xy, we have ...
x^2 +y^2 = -xy
Factoring the expression of interest, we have ...
x^3 -y^3 = (x -y)(x^2 +xy +y^2)
Substituting for xy using the first expression we found, this is ...
x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0
The value of x^3 -y^3 is 0.
Answer:
...
Step-by-step explanation:
..
<u>Solution:</u> 48cm/s^2
<u>Working:</u>
A = s^2
Derivate s^2 (as it is area formula) which gives
dA/dt = 2s dL/dt
dL/dt = 6cm/s
Hence,
2(6) = 12
Side: 4cm
Hence,
dA/dt = (4)(12) = 48cm/s^2
<em>Feel free to mark this as brainliest :D</em>
