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Inessa05 [86]
3 years ago
15

E=I×R and P=E×I what is the formula that will solve for R when only E and I are known

Mathematics
1 answer:
blagie [28]3 years ago
4 0

You wrote it there yourself, at the beginning of your question.

You wrote                             E       =  I  x  R

Divide each side by  ' I ' :    E / I  =  R

That's what you're asking for. ^

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50 points!!! Will mark brainliest
Murrr4er [49]

Answer:

x=20

Step-by-step explanation:

form a ratio

28:7

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x:5

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3 0
2 years ago
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(X^2+ x– 12) (x^2+ 10x + 25)
yulyashka [42]

Solution:

  • (x² + x – 12)(x² + 10x + 25)
  • => (x⁴ + 10x³ + 25x²) + (x³ + 10x² + 25x) + (-12x² - 120x - 300)
  • => x⁴ + 10x³ + 25x² + x³ + 10x² + 25x - 12x² - 120x - 300
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The only term that has a x-variable is "-95x".

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6 0
2 years ago
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For which function does f(14)=23?
NARA [144]

Answer:

Third item in the list

Step-by-step explanation:

Third function:  f(x) = x + 9.  If we substitute 14 for x, we get f(14) = 14 + 9 = 23.

3 0
3 years ago
The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea
zheka24 [161]

Answer:

$301 - $397

Step-by-step explanation:

Using the Empirical rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ .

From the above question,

Mean = 349 , standard deviation = 24.

Confidence interval = 95%

Using 2)95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ – 2σ

= 349 - 2(24)

= 349 - 48

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μ + 2σ

349 + 2(24)

= 349 + 48

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Therefore, according to the standard deviation rule, approximately 95% of the students spent between $301 and $397 on textbooks in a semester.

8 0
3 years ago
Round 14.57 to the nearest whole number.
lesya [120]
15 because 14.57 the .57 is above 50 therefore you go up!
3 0
2 years ago
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