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2 years ago

Write 90,523 in Word form

Mathematics

2 answers:

Troyanec [42]2 years ago

7 0

Ninety thousand five hundred twenty three

azamat2 years ago

3 0

Ninety thousand five hundred twenty three

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Help please its overdue

Eduardwww [97]

Answer:

B) 4cm

Step-by-step explanation:

Hope this helps! Pls give brainliest!

6 0

2 years ago

Please Help! Algebra 2!

eduard

Answer:

The interest rate of the account is $3\%$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=14\ years\\ P=\$1,863\\ A=\$2,830.97\\n=4$

substitute in the formula above and solve for r

$\$2,830.97=\$1,863(1+\frac{r}{4})^{4*14}$

$(2,830.97/1,863)=(1+\frac{r}{4})^{56}$

$(2,830.97/1,863)^{1/56}=(1+\frac{r}{4})$

$[(2,830.97/1,863)^{1/56}-1]=\frac{r}{4}$

$r=4*[(2,830.97/1,863)^{1/56}-1]\\ \\r= 0.03$

Convert to percent

$r= 0.03*100=3\%$

8 0

2 years ago

Find the 7th term in the<br> sequence<br> -1, -3, -9,...

mestny [16]

Answer:

The answer is 729

Step-by-step explanation:

to get the next term, the sequence multiples the previous number by -3

1 * -3 = -3

-3 * -3 = 9

and so on.

To get the 7th term:

-27 * -3 = 81 (5th term)

81 * -3 = -243 (6th)

-243 * -3 = 729 (7th)

7 0

2 years ago

Read 2 more answers

What are the accounting concepts

qwelly [4]

The accounting concepts are business entity, going concern, historical cost, conservatism, consistency etc.

5 0

2 years ago

Prove the following statement.

gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form $2k+1$ where $k\in \mathbb{Z}$ . Consider the following cases.

Case 1. If $k$ is even we have: $(2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1$ .

If we denote by $m=2s^2+2$ we have that $(2k+1)^{2}=8m+1$ .

Case 2. if $k$ is odd we have: $(2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1$ .

If we denote by $m=2s^{2}+24s+1$ we have that $(2k+1)^{2}=8m+1$

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0

2 years ago