Question

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

Answer 1

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = $-\frac{2}{5} x + \frac{19}{5}$

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

$3 = -\frac{2}{5} (2) + \frac{19}{5}$

$3 = -\frac{4}{5} + \frac{19}{5}$

3 = 15/5

3 = 3