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MAXImum [283]
4 years ago
14

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

Mathematics
1 answer:
rosijanka [135]4 years ago
8 0

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = -\frac{2}{5} x + \frac{19}{5}

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

3 = -\frac{2}{5} (2) + \frac{19}{5}

3 = -\frac{4}{5} + \frac{19}{5}

3 = 15/5

3 = 3

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What percent of 250 is 100?
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Answer:

40%

Step-by-step explanation:

100 is 4p% of 250

hope it helped!

7 0
2 years ago
-6y^2 + 9y^2 - y - 9 - 7y^2 + 1 + 10y + 3y
taurus [48]

Answer: -4y^(2)+12y-8

Step-by-step explanation: Combine like terms

6 0
3 years ago
Read 2 more answers
Please help in math I give lots of points.
disa [49]

\text{Put the value of x to the expression}\\\\\sqrt{x+3};\ x=15\\\\\sqrt{15+3}=\sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=\boxed{3\sqrt2}


\text{Put the value of x to the expression}\\\\\dfrac{6}{\sqrt{x}},\ x=3\\\\\dfrac{6}{\sqrt3}=\dfrac{6\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\dfrac{6\sqrt3}{3}=\boxed{2\sqrt3}


\text{Put the value of x to the expression}\\\\4\sqrt{x+1}-3\sqrt{2x+6},\ x=3\\\\4\sqrt{3+1}-3\sqrt{2(3)+6}=4\sqrt4-3\sqrt{6+6}=4(2)-3\sqrt{12}\\\\=8-3\sqrt{4\cdot3}=8-3\sqrt4\cdot\sqrt3=8-3(2)\cdot\sqrt3=\boxed{8-6\sqrt3}

8 0
3 years ago
What is:<br><br> 34983÷69 (NO CALCULATORS - HAS TO HAVE A REMAINDER PLEASE)<br><br> 10183÷81
lesya [120]
The first one shouldn't have a remainder

The answers are 507 and 125.75 or 125.7
8 0
4 years ago
You are standing on the corner of 4th Street and 4th Avenue in a city with a rectangular street system similar to New York’s (bu
TEA [102]

Step-by-step explanation:

To get from point (4,4) to (10,10), it is the same as ordering 6 Upward and 6 Right arrows in a straight line.

=> 12C6 = 924.

However there is a restriction that we cannot have 3 Upward and 3 Right arrows as our first 6 arrows.

=> 6C3 * 6C3 = 20 * 20 = 400

Hence there are 924 - 400 = 524 different ways.

4 0
3 years ago
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