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anygoal [31]
3 years ago
15

Which expression represents the distance -3 and 5 on the number line?

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
D 8 spaces 
-3-5 is -8 absolute value is distance from 0 which is 8
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Whats 3.8412 in place values
ELEN [110]
3 in the hundred-thousand place, 8 in thousands place, 4 in the hundreds place, 1  in the tens place, 2 in the one's place.
5 0
3 years ago
What is the difference between advanced calculus and real analysis?
eduard
<span>The content of any course depends on where you take it--- even two courses with the title "real analysis" at different schools can cover different material (or the same material, but at different levels of depth).

But yeah, generally speaking, "real analysis" and "advanced calculus" are synonyms. Schools never offer courses with *both* names, and whichever one they do offer, it is probably a class that covers the subject matter of calculus, but in a way that emphasizes the logical structure of the material (in particular, precise definitions and proofs) over just doing calculation.

My impression is that "advanced calculus" is an "older" name for this topic, and that "real analysis" is a somewhat "newer" name for the same topic. At least, most textbooks currently written in this area seem to have titles with "real analysis" in them, and titles including the phrase "advanced calculus" are less common. (There are a number of popular books with "advanced calculus" in the title, but all of the ones I've seen or used are reprints/updates of books originally written decades ago.)

There have been similar shifts in other course names. What is mostly called "complex analysis" now in course titles and textbooks, used to be called "function theory" (sometimes "analytic function theory" or "complex function theory"), or "complex variables". You still see some courses and textbooks with "variables" in the title, but like "advanced calculus", it seems to be on the way out, and not on the way in. The trend seems to be toward "complex analysis."  hope it helps

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8 0
3 years ago
A) y = 7sin (x - 40°) + 14<br> describe transformation
Ann [662]

Answer:

sorry sir i dont really know sir

6 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Vinil7 [7]

Answer:

a)

X[bar]_A= 71.8cm

X[bar]_B= 72cm

b)

M.A.D._A= 8.16cm

M.A.D._B= 5.4cm

c) The data set for Soil A is more variable.

Step-by-step explanation:

Hello!

The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)

To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.

The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.

Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.

X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.

a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:

X[bar]= ∑X/n

For soil A

Observations:

61, 61, 62, 65, 70, 71, 75, 81, 82, 90

The total of observations is n_A= 10

∑X_A= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718

X[bar]_A= ∑X_A/n_A= 218/10= 71.8cm

For Soil B

Observations:

59, 63, 69, 70, 72, 73, 76, 77, 78, 83

The total of observations is n_B= 10

∑X_B= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720

X[bar]_B= ∑X_B/n_B= 720/10= 72cm

b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.

To calculate the mean absolute dispersion you have to:

1) Find the mean of the sample (done in the previous item)

2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|

3) Add all absolute differences

4) Divide the summation by the number of observations (sample size,n)

For Soil A

1) X[bar]_A= 71.8cm

2) Absolute differences |X_A-X[bar]_{A}|

|61-71.8|= 10.8

|61-71.8|= 10.8

|62-71.8|= 9.8

|65-71.8|= 6.8

|70-71.8|= 1.8

|71-71.8|= 0.8

|75-71.8|= 3.2

|81-71.8|= 9.2

|82-71.8|= 10.2

|90-71.8|= 18.2

3) Summation of all absolute differences

∑|X_A-X[bar]_A|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6

4) M.A.D._A=∑|X_A-X[bar]_A|/n_A= 81.6/10= 8.16cm

For Soil B

1) X[bar]_B= 72cm

2) Absolute differences |X_B-X[bar]_B|

|59-72|= 13

|63-72|= 9

|69-72|= 3

|70-72|= 2

|72-72|= 0

|73-72|= 1

|76-72|= 4

|77-72|= 5

|78-72|= 6

|83-72|= 11

3) Summation of all absolute differences

∑ |X_B-X[bar]_B|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54

4) M.A.D._B=∑ |X_B-X[bar]_B|/n_B= 54/10= 5.4cm

c)

If you compare both calculated mean absolute deviations, you can see M.A.D._A > M.A.D._B. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.

I hope this helps!

7 0
3 years ago
Eight friends started a business. They will wear either a baseball cap or a shirt imprinted with their logo while working. They
posledela

Answer:The system of equations to describe the situation are

c + y = 8

6c + 3y = 36

Step-by-step explanation:

Let c represent the number of shirts.

Let y represent the number of caps.

Eight friends started a business. They will wear either a baseball cap or a shirt imprinted with their logo while working. This means that

c + y = 8 - - - - - - - - - - -1

They want to spend exactly $36 on the shirts and caps. Shirts cost $6 each and caps cost $3 each. This means that

6c + 3y = 36 - - - - - - - - - - 2

4 0
3 years ago
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