Question

I neeed someone's HELP PLEASE!!!!!!!!!!!!!!!!!!!!11

Answer 1

You need to combine the numerator into one fraction and the denominator into one fraction so you can flip and multiply.

$Numerator\\ \\ \frac{2}{x} + 3( \frac{x}{x} ) = \frac{2+3x}{x} \\ \\ Denominator \\ \\ 1 ( \frac{8x}{8x}) - \frac{1}{8x} = \frac{8x- 1}{8x} \\ \\ flip-multiply \\ \\ \frac{2+3x}{x} ( \frac{8x}{8x-1} ) = \frac{8(2+3x)}{8x-1} = \frac{16+24x}{8x-1}$

For the second question, factor everything.

$\frac{(q+8)(q-1)}{(q-4)(q+1)}$

Domain is the restriction on q. (remember denominator ≠ 0)
So q ≠ 4 or -1