What are the terms in the expression 2x-4y+8

What is the equation of the line with a x-intercept of 5 and a point (-2, -14)?

mart [117]

Answer:

y = 2x - 10

Step-by-step explanation:

Look at the attached photo for work

You just need to use the slope formula to get the slope and then the point slope formula to get the final equation.

6 0

3 years ago

How do u write 2/400=2/400÷4/4=0.5/100= as a percent

Vlad1618 [11]

Answer:

0.5%.

Step-by-step explanation:

The definition of percent is 'parts per 100'.

0.5 / 100 = 0.5 percent.

7 0

3 years ago

I need to find the answer to these questions in about 10 minutes or I'm screwed. please help me out.

Savatey [412]

For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.

For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.

For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of a line segment is the perpendicular bisector of the segment.

7 0

3 years ago

Carlos has used 40 cell phone minutes each day for one full week. His cell phone plan allows for a total of 320 minutes per week

sammy [17]

40 minutes*7 days of the week= 280 minutes a week. So, 320-280= 40 minutes left over. 40:320= 1:8. You were correct!

5 0

3 years ago

A small combination lock on a suitcase has 55 wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar

den301095 [7]

Suppose $a_n$ is the number of possible combinations for a suitcase with a lock consisting of $n$ wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for $n+1$ wheels, or $a_{n+1}$ is given recursively by the formula

$a_{n+1}=9a_n$

starting with $a_1=10$ (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

$a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n$

This means a lock with 55 wheels will have

$a_{55}=10\times9^{54}$

possible combinations (a number with 53 digits).

7 0

3 years ago