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MakcuM [25]
3 years ago
11

Solve for e:(-7)=e/3+14? show your work

Mathematics
1 answer:
Semmy [17]3 years ago
8 0
-7 = \frac{e}{3} + 14
take 14 to the other side
-7 -(14) = \frac{e}{3}
-21 = \frac{e}{3}
Multiply by 3 on either sides to isolate e and to find a value

-21 × 3 = \frac{e}{3} × 3
3 and 3 cancels out

-63 = e
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What is the length of line segment PQ? If you can please explain, thanks.
nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

\Rightarrow 4\times (x+4) = 6^2

\Rightarrow 4x+16 = 36

Subtract 16 from both sides.

\Rightarrow 4x+16-16 = 36-16

\Rightarrow 4x =20

Divide by 4 on both sides.

$\Rightarrow\frac{4x}{4}=\frac{20}{4}

\Rightarrow x = 5

The length of line segment PQ is 5 units.

5 0
4 years ago
Read 2 more answers
What's the answer ?????
kow [346]
Okay, so all this question wants you to do is plug in 2 for x and solve for your output, aka y.

y = -4x² - 8

when x = 2....
y = -4(2)² - 8

y = -16 - 8
y = -24

so, when your input is 2, your output is -24.
4 0
3 years ago
I need help asap please and thank you
Juliette [100K]

Answer:

100

Step-by-step explanation:

14. in × 7 in = 98. in So 98 Rounded to the nearest Tenth is 100. in

4 0
3 years ago
After being rearranged and simplified, which of the following equations could
masha68 [24]

Answer:

C and D

Step-by-step explanation:

The quadratic formula is

x= (-b±√b²-4ac)/2a

The formula uses the numerical coefficients in the quadratic equation.

The general quadratic equation is ax²+bx+c where a, b and c are the numerical coefficients

So, lets try and see;

A.

5x+4=3x^4-2\\\\=3x^4-5x-2-4\\=3x^4-5x-6\\a=3,b=-5,c=-6

But due to the fact that  in this equation you have x⁴, the equation is not a quadratic equation thus can not be solved using this formula

B

-x^2+4x+7=-x^2-9\\\\\\=-x^2+x^2+4x+7+9\\=4x+16

C

9x+3x^2=14+x-1\\\\\\=3x^2+9x-x-14+1\\\\=3x^2+8x-13\\\\\\a=3,b=8,c=-13\\

D.

2x^2+x^2+x=30\\\\\\=3x^2+x-30\\\\\\a=3,b=1,c=-30

From the checking above, the equations will be C and D

7 0
3 years ago
Read 2 more answers
Help!!!^^^^^^^^^^^^^^
zheka24 [161]

Answer:

woaahhh

Step-by-step explanation:

3 0
3 years ago
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