For
(x-h)^2=4p(y-k)
vertex is (h,k)
distance from vertex to directix=p=distance from vertex to focus
|4p|=focal width
remember, focus is on the side of the parabola where it opens and directix is at the back
when p is negative, it opens down
when p is positive, it opens up
look at equation
-1/40(x-0)^2=(y-0)
times -40 to both sides
(x-0)^2=-40(y-0)
(x-0)^2=4(-10)(y-0)
vertex=(0,0)
p=-10,it's negative so it opens down
focus is 10 units below vertex (y direction)
focus=(0,-10)
diretix is 10 above
directix is y=10
focal width=|4p|=|4(-10)|=|-40|=40
vertex=(0,0)
focus=(0,-10)
directix is y=10
focal width=40 units
Answer:
adddition is the first
Step-by-step explanation:
BODMAS
Answer:
(x+y)x^y
Step-by-step explanation:
i hope it helped you. thankyou
The mean and standard deviation of the x sampling distribution for each of the following sample sizes will be 
.
<h3>What is the distribution of the sample mean for large samples?</h3>
Suppose X has a distribution with mean 
and standard deviation 
then,
the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with a mean equal to the mean of X, and a standard deviation equal to 
Symbolically, we write it as:
A random sample is selected from a population with a mean = of 100 and a standard deviation = of 10.
The mean and standard deviation of the x sampling distribution for each of the following sample sizes.
If N=41
If N=130
Learn more about standard normal distribution here:
brainly.com/question/10984889
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Answer:
1. C) 3
2. D) -1
3. D) 7^2 - 8*2 - 16
4. B) 75
5. B) 6^2 + (2 - 8)*sqrt(81)
Step-by-step explanation:
1. (10 - (6-4)^2)/2
= (10 - 2^2)/2
= (10 - 4)/2
= 6/2
= 3
2. PEMDAS states that Multiplication is before Subtraction
8 - (5^2-7)/2
= 8 - (25-7)/2
= 8 - 18/2
= 8 - 9
= -1
3. D) 7^2 - (8*2) - 16
= 49 - 16 - 16
= 49 - 32
= 17
4. 3(2 + 3)^2
= 3(5)^2
= 3(25)
= 75
5. 6^2 + (2 - 8)*sqrt(81)
= 36 + (-6*9)
= 36 - 54
= -18
