Im slow soooooooooooooo i need help

Question 14. When solving the equation -14 = 7x + 6 what will the next stage of your working be?

mr_godi [17]

Answer:

You would subtract 6 from each side.

Step-by-step explanation:

- 14 = 7x + 6

Subtract 6 from each side:

- 14 - 6 = 7x + 6 - 6

7x = - 20

Divide each side by 7:

7x ÷ 7 = - 20 ÷ 7

x = 2 and 6/7

4 0

3 years ago

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

4 years ago

Marcus loves baseball and wants to create a home plate for his house. Marcus needs to calculate the area of the home plate at th

Tema [17]

Top triangle area: 7×8 /2 -> 56/2= 28
right triangle area: 6×5 /2 -> 30/2= 15
rectangle area: 5×8 -> 40
40+28+15
68+15
83 in^2

7 0

4 years ago

Read 2 more answers

six people, including A,B, and C, form a queue in a random order (all 6! orderings are equiprobable). Consider the event "B is b

mojhsa [17]

Answer:

There is a 1.39% probability that "B is between A and C in the queue".

Step-by-step explanation:

The first step to solve this problem is find the total number of possible orderings:

The first person of the queue can be any of the six. The second, can be any but the first, so five.

So

There are 6*5*4*3*2*1 = 720 total queue orderings.

Now we find the number of queues that B is between A and C. So:

We have:

B as the second, A as the first and C as the third

B as the second, C as the first and A as the third

B as the third, A as the second and C as the fourth

B as the third, C as the second and A as the fourth

B as the fourth, A as the third and C as the fifth.

B as the fourth, C as the third and A as the fifth.

B as the fifth, A as the fourth and C as the sixth.

B as the fifth, C as the fourth and A as the sixth.

So 8 total outcomes in which B is between A and C.

What is its probability?

$P = \frac{8}{720} = 0.0111$

There is a 1.11% probability that "B is between A and C in the queue".

6 0

3 years ago

Read 2 more answers

Dropping less than two inches per mile after emerging from the mountains, a river drains into the ocean. One day's discharge a

Tanya [424]

Answer:

dont know sorry

Step-by-step explanation:

4 0

4 years ago