The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
B. -90
Step-by-step explanation:
a1=9; d=-3
a34=9-3(33-1)=-90
Answer:
A
Step-by-step explanation:
The perimeter is more since the shape gained many new sides but the area is less because the rectangle lost a little square
The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.
Answer:
P(L ≤ l) =P (1-l ≤ U ≤ l)= l- ( 1 - l ) = 2 l - 1
Step-by-step explanation:
let assume that stick has length 1.Random variable L that make length of a longer piece and random variable U that mark point .See that L < l means that
U≤ l and 1-U ≤l
P(L ≤ l) =P (1-l ≤ U ≤ l)= l- ( 1 - l ) = 2 l - 1
this means 1-l≤U≤l
so we have
if we have L [1/2,1]
then apply the formula we have E(L)=3/4
