Answer:
I think the answer would be C
Step-by-step explanation:
Answer:
hi
Step-by-step explanation:
rfshs hmm jtutq JK jehewyywgu
Hey there!
Let x be boy 1's age, and y be boy 2's age (younger).
Firstly, we know that x+y=24
6y-4=3x+5 <== we have this right here. (using the rules given by the question)
We can use all the equations to help find the answer.
x+y=24
x+y (-y)= 24(-y)
x=24-y
Plug that into x in the equation we made above.
6y-4= 3(24-y)+5
6y-4= 72-3y+5
Add 4 to each side.
6y= 81 -3y
9y=81
y=9
We know the younger boys age is 9.
We can plug that in to find the older one's age.
x+9= 24
x= 15
The boy's ages are 9 and 15.
I hope this helps!
~kaikers
-19
-18
-2
-6
Could be pretty much be anything below
Answer:
Below in bold.
Step-by-step explanation:
No repetition.
There are a total of 7 numbers.
For the number to be even it must end in 0, 2 or 8.
The other 3 numbers will be the number of permutations of 3 from the 6 other numbers.
Number of 4 digit numbers ending in 0
= 6P3 = 6! / 6-3!
= 120.
Now the number could also end in 2 or 8,
so there are 3*120 = 360 4-digit even numbers (no repetition).
With repetition.
There are 3 * 7^3 = 1029 with repetition.
