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3 years ago

12

A restaurant charges $3 for a soda and it includes free unlimited refills. If this situation were represented as a function, wha

t would be the slope?

1 answer:

omeli [17]3 years ago

4 0

Answer:

This would be a constant..

(3,0)

(3,0)

(3,0)

(3,0)

So this is a constant and it goes in a straight line across the coordinate grid.

Hope this helps a little!!

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If you have 6 dollars and you use 2 how much is that

iragen [17]

Answer:

4 dollars

Step-by-step explanation:

8 0

3 years ago

Find the zeros of the polynomial x^2 + 8x + 16

Scorpion4ik [409]

hey mate,

$x^2 + 8x + 16 = 0$

<=>

$(x+4)^2 = 0$

As we know that $(a+b)^2 = a^2+b^2+2ab$

then

$(x+4)^2 = 0$

<=> (x+4) = 0

<=> x = -4

so there is one solution x = -4

thanks

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3 years ago

Simplify the radical expression by rationalizing the denominator. <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B%20%5Csq

Rashid [163]

$\bf \cfrac{2}{\sqrt{42}}\cdot \cfrac{\sqrt{42}}{\sqrt{42}}\implies \cfrac{2\sqrt{42}}{(\sqrt{42})^2}\implies \cfrac{2\sqrt{42}}{42}\implies \cfrac{\sqrt{42}}{21}$

6 0

3 years ago

I NEED HELP ASAP IT IS FOR CHRISTMAS!!!!!!THESE ARE ALL MY POINTS!!

vladimir2022 [97]

Answer:

They should pay $12 each

3 0

2 years ago

Read 2 more answers

Solve 2x2 − 12x + 20 = 0.<br><br> 3 ± i<br> 3 ± 2i<br> 1 ± 2i<br> 2 ± 3i

makkiz [27]

This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
x=[-b+/-sqrt(b^2-4ac)]/(2a)
from our equation, a=2,b=-12 and c=20
x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
x=[12+/-sqrt(144-160]/4
x=[12+/-sqrt(-16)]/4
x=[12+/-4i]/4
x=[3+\-i]
the answer is A] 3+/-i

7 0

2 years ago