Nice job inputting the expression.
The cube root is a 1/3 power. The 4 in the denominator is a -4 power in the numerator. When we have powers of powers we multiply them all together. When we have a product to a power we have to raise each factor to the power.
We get to choose whether we want a fraction at the end or negative exponents. Because of the constant 16 in the denominator I chose fraction.
![\dfrac{1}{( \sqrt[3]{8p^6})^4} = ( \sqrt[3]{8p^6})^{-4} = ( (8p^6)^{\frac 1 3})^{-4} =(8^{\frac 1 3})^{-4} p^{(6(-4)/3)} = 2^{-4} p^{-8} = \dfrac{1}{16p^8}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%28%20%5Csqrt%5B3%5D%7B8p%5E6%7D%29%5E4%7D%20%3D%20%28%20%5Csqrt%5B3%5D%7B8p%5E6%7D%29%5E%7B-4%7D%20%3D%20%28%20%288p%5E6%29%5E%7B%5Cfrac%201%203%7D%29%5E%7B-4%7D%20%3D%288%5E%7B%5Cfrac%201%203%7D%29%5E%7B-4%7D%20p%5E%7B%286%28-4%29%2F3%29%7D%20%3D%202%5E%7B-4%7D%20p%5E%7B-8%7D%20%3D%20%5Cdfrac%7B1%7D%7B16p%5E8%7D)
Answer: 1/(16p⁸)
Answer:
107 :)
Step-by-step explanation:
In total there are 53+8+155+17+145+10+98+2=488 physicians of aerospace medicine. 45-54 year-old males account for 145/488 of this population, so they should account for that fraction of the central angle of the circle graph also. Since there are 360 degrees in the central angle to divide up among the groups, the 45-54 year-old male group should get 145/488 x 360 which rounds to about 107 degrees.
The simplified forms of the given expressions are
a. 32x
b. 0
c. -26t + 14x
d. 3t
<h3>Simplifying an expression </h3>
From the question, we are to simplify the given expressions by adding or subtracting
a. (10x) + (22x)
= 32x
b. (-6x) - (-6x)
= -6x + 6x
= 0
c. (-13t) + (14x) - (+13t)
= -13t + 14x - 13t
Collect like terms
= -13t -13t + 14x
= -26t + 14x
d. (-4t) + (+4t) - (-3t)
= -4t + 4t + 3t
= 3t
Hence, the simplified forms of the given expressions are
a. 32x
b. 0
c. -26t + 14x
d. 3t
Learn more on Simplifying an expression here: brainly.com/question/723406
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Answer:
-12x = 60
Step-by-step explanation:
This is the type of problem that you just have to do a bunch of times until you get it right -- I don't think there's anything I can tell you that'll help you immediately. Ask for your teacher for more exercises of this sort or look it up online.
Good luck!
