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Drupady [299]
3 years ago
13

Como calculo uma conversao de 38 ºF P/ ºC

Mathematics
1 answer:
jeka943 years ago
6 0

           °C  =  5/9 (°F - 32)

           °C  =  5/9 (38 - 32)

               =  5/9 (6)

               =  30/9  =   3 e 1/3 .
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Un arquitecto ha pagado en un corralón un total de $ 130 por 20 Ladrillos, 5 kg de Arena y 10 kg de Cemento. Calcular el precio
Advocard [28]

Answer:

1 ladrillo cuesta 1 dólar.    1 brick costs 1 dollars.

1 kg de cemento cuesta 3 dólares: 1 kg cement costs 3 dollars

1 kg de arena cuesta $ 16: 1 kg sand costs $ 16

Step-by-step explanation:

Spanish

Deje que los ladrillos, la arena y el cemento se denoten por b, sy c. Luego, de acuerdo con la condición dada

20b + 5s + 10c = $ 130 --- ecuación 1

1c = 3b ------ ecuación 2

1s = 4c + 4b ------ ecuación 3

Poniendo la ecuación 2 en la ecuación 3

1s = 4 (3b) + 4b

1s = 16b ---------- ecuación 4

20b + 5s + 10 (3b) = $ 130

50b + 5s = 130 --- ecuación 5

Poniendo la ecuación 4 en la ecuación 5

50 b + 5 (16b) = 130

50 b + 80b = 130

130 b = 130

b = 130/130 = $ 1 ------- ecuación a

1 ladrillo cuesta 1 dólar.

Poner el valor de costo de 1 ladrillo en estas ecuaciones

1c = 3b ------ ecuación 2

1s = 4c + 4b ------ ecuación 3

1c = 3 (1) = $ 3 -------- ecuación b

1 kg de cemento cuesta 3 dólares

1s = 4c + 4b

1 s = 4 (3) + 4 (1)

1 s = 12 + 4

1s = $ 16 ------ ecuación c

1 kg de arena cuesta $ 16

Poner valores de la ecuación a, b, c en la ecuación 1

20b + 5s + 10c = $ 130

20 (1) + 5 (16) + 10 (3) = 130

20 + 80 + 30 = 130

130 = 130 ------------ por lo tanto probado

English

Let the bricks , sand and cement be denoted by b, s and c. Then according to the given condition

20b+ 5s+ 10c= $130--- equation 1

1c= 3b------ equation 2

1s= 4c+4b------ equation 3

Putting equation 2 in equation 3

1s= 4(3b) + 4b

1s= 16b---------- equation 4

20b+ 5s+ 10(3b)= $130

50b + 5s= 130--- equation 5

Putting equation 4 in equation 5

50 b + 5 (16b) = 130

50 b+ 80b= 130

130 b= 130

b= 130/130= $1------- equation a

1 brick costs 1 dollars.

Putting the cost value of 1 brick in these equations

1c= 3b------ equation 2

1s= 4c+4b------ equation 3

1c= 3(1)= $3-------- equation b

1 kg cement costs 3 dollars

1s= 4c+4b

1s= 4(3) + 4(1)

1s= 12+4

1s= $16 ------ equation c

1 kg sand costs $ 16

Putting values from equation a, b, c in equation 1

20b+ 5s+ 10c= $130

20 (1) + 5 (16) + 10 (3)= 130

20 + 80 + 30 = 130

130 = 130   ------------ hence proved

8 0
2 years ago
If you factor y^2-81 COMPLETELY, would it just be (y-9)(y+9), or would it be something like y(3)(-3)y(3)(3)?
Vladimir79 [104]
That would be (y - 9)(y +9). When two binomials are multiplied, the distributive property is applied. However, if the equation is <span>y(3)(-3)y(3)(3), you just simply multiply them altogether. That would be -81y^2, which is not equivalent with y^2 - 81.</span>
4 0
3 years ago
I need help on 2,5 10-12,29 please anyone !!
AfilCa [17]

Answer:

2:1/2

5:16/24

10:Movie B

11:Movie D

12:2/3

I can't see 29. If you show it, then i will solve it.

Step-by-step explanation:

3 0
3 years ago
Write the expression using a single exponent.
Ipatiy [6.2K]

Answer:  D.  7^11

Reason:

The rule we use is a^b*a^c = a^{b+c}

When multiplying exponentials of the same base, we add the exponents.

The exponents 5 and 6 add to 5+6 = 11

So,

7^5 \times 7^6 = 7^{5+6} = 7^{11}

The base stays the same the entire time.

6 0
2 years ago
Read 2 more answers
Round each number to the nearest ten. 283
arsen [322]
283 rounded to the nearest ten is 280
When rounding to the nearest ten look at the number to the right of the place you are rounding. In this case it is the 3. If the number is 5 or higher you go up to the nearest ten. If the number is lower than 5 like it is in this number you round down to the nearest ten.
5 0
3 years ago
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