An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
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3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
The answer is w⁻²/v⁻².
v/w raised to the second power is (v/w)²
(v/w)² = v²/w²
Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²
Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²
Let’s first write this in the slope form: y=mx+b.
m is the slope and b is the y intercept.
-2x-y=3
y=-2x-3
So the b, or the y intercept is -3
The answer should be 91 because for your total perimeter you add all the sides. So you already have your length of 75 which counts as 2 sides and equals up to 150. after you subtract your two sides from your perimeter you get 182. you then divide 182 by 2 to get your two remaining sides which gives you 91.
