All categories

3 years ago

If two cylinders are similar and the ratio between the lengths of their edges is 2:5 what is the ratio of their volumes

Mathematics

2 answers:

forsale [732]3 years ago

8 0

Answer: Thou answer shalt be Le letter B. 8:125

Hunter-Best [27]3 years ago

7 0

We know that
[scale factor] is equal to the ratio <span>between the lengths of their edges
so
scale factor=2/5

volume smaller cylinder/volume larger cylinder=[scale factor]</span>³
volume smaller cylinder/volume larger cylinder=[2/5]³---> 8/125

the answer is
8/125

You might be interested in

The function f(x)=−4x4+3x3−2x2−x+5 is/has A. order 2 rotational symmetry about the origin

Monica [59]

The answer choice which describes the function is; Choice B; neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.

<h3>What is rotational symmetry?</h3>

Rotational symmetry, otherwise termed radial symmetry, is the characteristic of a shape when it looks the same after some rotation by a partial turn. On this note, since the function represents a quartic graph, it follows that the function has neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.

Therefore, the function f(x) = −4x⁴ + 3x³ − 2x² − x + 5 is neither symmetry about the y-axis nor has order 2 rotational symmetry about the origin.

Read more on rotational symmetry;

brainly.com/question/15178808

#SPJ1

3 0

2 years ago

Express as a trinomial: (2x-3)(x 5)

Illusion [34]

I am assuming the expression is (2x-3)(x+5) or (2x-3)(x-5). I will teach you how to solve for both as I am not sure which one you are asking for. There are 4 steps to multiplying.

1) Multiply the x times the second x
2) Multiply x times the second number
3) Multiply the number by the second x
4) Multiply the number by the second number.

(2x*x)+(2x*5)+(-3*x)+(-3*5)=(2 $x^{2}$ )+(10x)+(-3x)+(-15)=2 $x^{2}$ +7x-15

(2x*x)+(2x*-5)+(-3*x)+(-3*-5)=(2 $x^{2}$ )+(-10x)+(-3x)+(15)=2 $x^{2}$ -13x+15

Your answer is 2 $x^{2}$ +7x-15 or 2 $x^{2}$ -13x+15. Does that answer your question?

6 0

3 years ago

Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7

Lapatulllka [165]

The first equation is $y-2x+1=0$

$y=2x-1$ (Equation 1)

The second equation is $4x^{2}+3y^{2}-2xy=7$ (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

$4x^{2}+3(2x-1)^{2}-2x(2x-1)=7$

$4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7$

by simplifying the given equation,

$12x^{2}-10x-4=0$

$6x^{2}-5x-2=0$

Using discriminant formula,

$D=b^{2}-4ac$

$D=25-4 \times 6 \times -2 = 73$

Now the formula for solution 'x' of quadratic equation is given by:

$x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}$

$x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}$

Hence, these are the required solutions.

8 0

3 years ago

Help me wiht this plssss

yulyashka [42]

Answer:

well you find. out how many all of them measure. and add them and then that answer multiply of the main number

Step-by-step explanation:

first add up all of the lengths and then find that answer multiply it to the main number and then you will get your anwer it's a 2 step problem

7 0

2 years ago

A circle with radius 4 inches is inscribed in an equilateral triangle. Find the area of the triangle.

LUCKY_DIMON [66]

The inscribed circle has its center at the point of intersection of the angle bisectors, which also happen to be the medians. Hence the altitude of the triangle is 3 times the radius, or 12 inches.

The side length of this triangle is 2/√3 times the altitude, so the area is

... Area = (1/2)·b·h = (1/2)·(24/√3 in)·(12 in)

... Area = 48√3 in² ≈ 83.1384 in²

7 0

3 years ago