Given :
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.
To Find :
How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.
Solution :
Mass of copper in 50 gm alloy = 
.
Mass of copper in 78 gm alloy = 
.
Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.
Percentage of copper in resulting mixture :
Hence, this is the required solution.
5510 = x + (x + 100) + (x + 200) + (x + 300) + (x + 400) + (x + 500) + (x + 600) + (x +700) + (x + 800) + (x + 900) = 10x + 4500
=> 10x = 5510 - 4500 = 1010
=> x = 1010 / 10 = 101
=> least prize = 101 and greatest prize = 101+ 900 = 1001.<----- answer
<h3><u>The length is equal to 25.</u></h3><h3><u>The width is equal to 15.</u></h3>
l = 2w - 5
2l + 2w = 80
We have a value for l, so we can plug it into the second equation to solve for w.
2(2w - 5) + 2w = 80
Distributive property.
4w - 10 + 2w = 80
Combine like terms.
6w - 10 = 80
Add 10 to both sides.
6w = 90
Divide both sides by 6.
w = 15
Now that we have a value for w, we can plug it into the original equation to solve for l.
l = 2(15) - 5
l = 30 - 5
l = 25
1.1301 is larger cuz 1.13 is same as 1.1300
Answer:
158
Step-by-step explanation:
10.89-2.99 = 7.90
.5/7.90=158
