The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
Answer:
y = x + 7
Step-by-step explanation:
First, set up the equation.
365x + 125 = 250x + 175
Second, combine like terms on the same side by subtracting 250x and 125 from both sides.
365x +125 = 250x + 175
-250x -125 -250x -125
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115x = 50
Third, divide both sides by 115 to solve for x.
115x = 50
---- ----
115 115
Fourth, simplify.
x=50/115=10/23 or 0.435
Answer:
1/30 or 3.333%
Step-by-step explanation:
Simply the answer is 7 ounces :D
