Answer:
h = 2.25 m
Step-by-step explanation:
<u><em>Given:</em></u>
Speed = v = 12 ft/sec
Acceleration due to gravity = g = 32 ft/sec²
<u><em>Required:</em></u>
Height = h = ?
<u><em>Formula:</em></u>
v = 
<u><em>Solution:</em></u>
For h, the formula will be:
=> h = 
=> h = 
=> h = 
=> h = 2.25 m
The answer is B) The transformation rule is (x, y) -> (x + 0, y + 4).
Answer:
<em>AB = 3π</em>
Step-by-step explanation:
<em>See attachment for correct format of question.</em>
Given
From the attachment, we have that
θ = 20°
Radius, r = 27
Required
Find length of AB
AB is an arc and it's length can be calculated using arc length formula.
<em>Substitute 20 for θ and 27 for r</em>
Hence, the length of arc AB is terms of π is 3π
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
the value of x would be 5.5
Step-by-step explanation:
This is true by multiplying 2 by 5 and a half
