SOMEONE PLEAZE HELP [20 POINTS!!!!!] SERIOUS ANSWERS ONLY

Which is an equation of the line through the origin and (3,4)? Please help

kondor19780726 [428]

B is the answers………..

8 0

3 years ago

How do I find X in this problem

pogonyaev

You know that BC is congruent to x so you need to solve for x using the ratio:
$\frac{12}{24}=\frac{x}{BC}$

So then we need to find BC.

We know:
$A=\frac{base \times height}{2}$
$28=\frac{BC \times 7}{2}$
Therefore BC =8

Then:
$\frac{12}{24}=\frac{x}{8}$
$x=8 \times \frac{12}{24} = 4$

4 0

3 years ago

4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B

AleksAgata [21]

Answer:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

$\hat p=\frac{63}{200}=0.315$ estimated proportion of lawyers had used some form of advertising for their business

$p_o=0.25$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.123)=0.0169$

The p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .

8 0

3 years ago

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot

lara [203]

Answer:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

$\hat p=0.66$ estimated proportion of voters that favored construction

$p_o=0.63$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:

Null hypothesis: $p \leq 0.63$

Alternative hypothesis: $p > 0.63$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0

3 years ago

The length of a rectangular board is 10 cm longer than its with. The width of the board is 26cm. The board is cut into 9 equal p

Margaret [11]

Answer: 26 cm × 4 cm or

36 cm × 2.89 cm

Step-by-step explanation:

The diagram of the board is shown in the attached photo

Width of the rectangular board is given as 26 cm

The length of a rectangular board is 10 cm longer than its with. This means that

Length of rectangular board = 26 +10 = 36 cm.

Area of rectangular board = length × width. It becomes

36 × 26 = 936cm^2

The board is cut into 9 equal pieces. This means that the area of each piece would be the area of the board divided by 9. It becomes

936 /9 = 104cm^2

The dimensions of the piece would be

Since area of each piece is 104 cm^2 and the width of the bigger board still corresponds to one side of each piece, the other side of each piece will be 104 /26 = 4 cm

Also, the board could have been cut along the length such that one side of the cut piece corresponds to the length of the original board (36 cm)

and the other side becomes

104 /36 = 2.89 cm

The possible dimensions are

26 cm × 4 cm or

36 cm × 2.89 cm

8 0

3 years ago