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3 years ago

In which triangle is cos x = 5/8?

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer:

triangle D............

Aliun [14]3 years ago

7 0

Triangle B

$cos \: x= \frac{adj}{hyp} = \frac{5}{8}$

If you need, always label your triangles!

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The shorter leg of a right triangle is 5 inches shorter than the longer leg. The hypotenuse is 5 inches longer than the longer l

Licemer1 [7]

Answer:

longer leg: 20 in

shorter leg: 15 in

hypotenuse: 25 in

Formulas:

Pythagorean Theorem

$c^2 = a^2 + b^2$

c ... hypotenuse

a ... one leg

b ... another leg

Pythagorean theorem is used in right triangles (triangles in which one angle is 90°).

Step-by-step explanation:

longer leg: x

shorter leg: x - 5

hypotenuse: x + 5

To find x (longer leg), let's use Pythagorean theorem.

$c^2 = a^2 + b^2\\(x+5)^2 = x^2 + (x-5)^2\\x^2 + 10x + 25= x^2 + x^2 -10x + 25\\x^2 + 10x = 2x^2 - 10x\\0 = x^2 - 20x$

Now let's factorize to get solutions for x.

$0 = x(x-20)$

First solution:

$x = 0$

Second solution:

$x - 20 = 0\\x = 20$

Since a side of a triangle has to be a positive number, x is equal to 20.

Now let's just substitute x back to get side lengths. From the question the lengths are in inches.

longer leg: x = 20 in

shorter leg: x - 5 = 20 - 5 = 15 in

hypotenuse: x + 5 = 20 + 5 = 25 in

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2 years ago

A cyclist travels 15km due north and then 18 km due east. How far is she from the starting point?

zavuch27 [327]

Answer:

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Step-by-step explanation:

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What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundre

nika2105 [10]

Answer:

Area of the triangle $\simeq$ 5.9 sq. ft. .

Step-by-step explanation:

Length of two sides of the triangle are, 2.7 feet and 3.4 feet and the angle between them is 40° .

So, the area of the triangle is given by,

$2.7 \times 3.4 \times \sin {40^{\circ}}$ sq. ft.

$\simeq 5.9$ sq. ft.

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3 years ago

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hichkok12 [17]

Answer: -129

Step-by-step explanation:

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3 years ago

Solve for B. R = x(A + B) B = (R-A)/X B = (A-Rx)/X B = (R-Ax)/X

Ivanshal [37]

R = x(A + B) solve for B
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