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IrinaVladis [17]
3 years ago
11

There are a total of 84 students in a drama club and a yearbook club. The drama club has 16 more students than the yearbook club

. How many students are in the drama club? the yearbook club?
Mathematics
1 answer:
vodomira [7]3 years ago
7 0
Y = yearbook club
d = drama club

y + d = 84
d = y + 16

now we sub y + 16 in for d in the first equation
y + d = 84
y + (y + 16) = 84
2y + 16 = 84
2y = 84 - 16
2y = 68
y = 68/2
y = 34 <=== yearbook club students

d = y + 16
d = 34 + 16
d = 50 <=== drama club students
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(please mark brain if this helps and is correct)

Step-by-step explanation:

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ex: 2x + 4   [2(0) + 4] = 0 + 4 = 4

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ex: 2x + 4   [2(1) + 4] = 2 + 4 = 6

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Read 2 more answers
The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"
svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 134, \sigma = 66

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

Z = \frac{X - \mu}{\sigma}

1.037 = \frac{X - 134}{66}

X - 134 = 66*1.037

X = 202.44

At least 202.44 mm in the top 15%.

5 0
3 years ago
86.75 as a fraction how did u get your awnser?
Zielflug [23.3K]
86.75 =86\frac{3}{4}
or as an improper \frac{347}{4}
3 0
3 years ago
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