Answer:
1st slot: 12
2nd slot: 48
Step-by-step explanation:
Hope this helps!
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
d
Step-by-step explanation:
range is how far the graph goes from bottom to top.
Find answer showing detailed workings in the image
We use the fact that x2+y2=1 This is the equation of the unit circle.
We know that x=-4/5, so plug this in and solve for y
x2+y2=1 <span>(−4/5)^2+y2=1</span> 16/25+y2=1 y2=1−16/25 y2=9/25 <span>y=−square root of 9/ 25</span>
y = -3/5
