Question

Write the equation of the line that passes through (-4, 8) and is parallel to the line that passes through (2, 1) and (-2, -1).

Answer 1

Answer:

Step-by-step explanation:

(2,1), (-2,-1)

slope(m) = (-1-1) / (-2 - 2) = -2/-4 = 1/2

parallel lines will have the same slope

y = mx + b

slope(m) = 1/2

(-4,8)...x = -4 and y = 8

now sub and find b, the y int

8 = 1/2(-4) + b

8 = -2 + b

8 + 2 = b

10 = b

so ur equation is : y = 1/2x + 10 <==

Answer 2

Answer:

$\displaystyle x - 2y = -20\:OR\:y = \frac{1}{2}x + 10$

Step-by-step explanation:

First, find the rate of change [slope]:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-1 - 1}{-2 - 2} = \frac{-2}{-4} = \frac{1}{2}$

Now plug [−4, 8] into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much more swiftly:

8 = ½[−4] + b

−2

$\displaystyle 10 = b \\ \\ y = \frac{1}{2}x + 10$

If you want it in Standard Form:

y = ½x + 10

- ½x - ½x

__________

−½x + y = 10 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]

−2[−½x + y = 10]

$\displaystyle x - 2y = -20$

I am joyous to assist you anytime.