0-300-150=-450 feet
-450 feet is the whale’s elevation
Given the data below <span>representing the body mass index (bmi) values for 20 females.
17.7 33.5 26.9 22.7 22.2 29.9 23.6 18.3 27.7 23.4 19.2 25.9 22.9 37.7 31.6 28.1 44.9 31.6 25.2 23.9
From the data above, we construct a frequency distribution beginning with a lower class limit of
15.0 and use a class width of 6.0 as follows:
Class iinterval: 15.0 - 21.0 21.0 - 27.0 27.0 - 33.0 33.0 - 39.0 39.0 - 45.0
Frequency: 3 9 5 2 1
From the frequency table, it can be seen that the frequencies started low, increased to a point and then decrease. It can also be seen that the highest frequency of the data is not at the center of the distribution, so the distribution is not symetric.
Therefore, the frequency
distribution does not appear to be roughly a normal distribution, because, "although the frequency start low, increase to some maximum, then decrease, the distribution is not symmetric."</span>
Domain is {1 ,2,3,4}
range is {3}
it's a function because each element in x has only one image in y
If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.
Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.
If we divide 500 into 10 we get 50:
500 / 10 = 50
That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:
1 x 50 = 50
So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.
Hope it helped,
BioTeacher101
