Answer:
PART C OF WHAT I CAN HELP IF YOU TELL ME
Answer:

Step-by-step explanation:
The area of the square is 36.
A = s^2
36 = s^2
s = sqrt(36)
s = 6
The side of the square has length 6.
All sides of a square are congruent, so all sides have length 6.
If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.
a^2 + b^2 = c^2
6^2 + 6^2 = c^2
36 + 36 = c^2
c^2 = 72




c is the diameter.
r is the radius, so it is half of the diameter.
c = d
r = d/2

Step-by-step explanation:
sec(x) = 1/cos(x)
and therefore, it behaves accordingly.
the minimum of cos(x) is the maximum of 1/cos(x).
it does not have any x-intercepts. for cos(x) = 1 (max) we get 1/1 = 1 for sec(x), which is the minimum.
mirrored to this, cos(x) = -1 gives us also -1 for sec(x).
sec(x) = 1/cos(x) can never have a result between -1 and +1.
cos(0) = 1, so also sec(x) = 1, and therefore (0, 1) is the y-axis intercept.
at every pi (beginning at 0) there is a horizontal tangent, but not an asymptote. the (vertical) asymptotes happen at every pi beginning at pi/2 and -pi/2.
therefore, only the third and fourth answer options are correct.