<span>how many hours they can work on a project.</span>
Answer:
A. client/server
Explanation:
Beacuse a Server or a client is what hold data for big companies like google and microsoft
Answer: Operational BI(Business Intelligence)
Explanation:Operational business intelligence is the tool that works on the organizational performance through evaluation and testing by analyzing the business process and data.It is rapid responding tool for the changing business pattern and demands.
Strategical, tactical and traditional business intelligence tool don't provide the evaluation of the business performance in the accordance with business trends rather having strategical approach, planned approach and traditional approach respectively.
Thus, the correct option is option(b).
Answer:
SCSI.
Explanation:
It is a set of ANSI-developed simultaneous interface requirements for connecting scanners, drives, printers, and many other devices to systems.
Although when Tim has such an outdated network system which is used as a backup by his corporation. Then hard drive may have gone wrong and required replacement. The connector used by the hard disk drive is not something he has ever seen before, but he upload photos of that on the community board of the organization to aid determine what kind of hard disk drive they will also have to order.
So, according to the following scenario he required SCSI cable.
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
