<span>Arrival protocols are the type of data protocols that convert data into standard formats that can be used by applications, such as email, Web browsers and Skype</span>
The answer is already given at the end of the question; solely by the magnitude or severity of expected harm
When assessing risks of harm associated with participation in a research study, the probability of harm and the risk of the severity of harm are two distinctive elements of risk that must be considered. In probability of harm, the fact that not all possible harms are equally probable should be considered. How these two elements occur is a crucial factor in determining the level of risk of harm in a study. Given the sensitivity of the information in the case scenario above, the probability that an individual subject could be identified is low while the magnitude of the possible risk of harm is high.
google or search through pvps
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
