Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
<u>Step-by-step explanation:</u>
We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,
Perimeter = 42 inches
⇒
width of printed area = x-3 & length of printed area = y-2:
area =
Let's find :
= , for area to be maximum = 0
⇒
And ,
∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
Answer: The solution is (3, -2)
This means that x = 3 and y = -2 pair up together.
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Explanation:
The solution is where the two lines cross. Note if we started at the origin (0,0) and moved to the right 3 units, and then down 2 units, we would arrive at the location (3, -2).
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As a way to check, we can plug x = 3 into each equation. We should get y = -2 as a result for each equation
y = (-5/3)x + 3
y = (-5/3)*3 + 3
y = -5+3
y = -2
The first equation is confirmed. Let's check the second equation
y = (1/3)x - 3
y = (1/3)*3 - 3
y = 1 - 3
y = -2
Both equations have the y value equal -2 when x = 3. Therefore, the overall solution is confirmed.
Answer:
t = -1, 2
Step-by-step explanation:
Step 1: Define
h(t) = -5t² + 5t + 10
Step 2: Factor
h(t) = -5(t² - t - 2)
h(t) = -5(t - 2)(t + 1)
Step 3: Find roots
0 = -5(t - 2)(t + 1)
0 = (t - 2)(t + 1)
t - 2 = 0
t = 2
t + 1 = 0
t = -1
That’s not enough information to say how long he could do it. He could go slower or faster than her but by how much if so. So it’s not enough info.
2x^2 + 8x - 12 = 0..divide by 2
x^2 + 4x - 6 = 0
x^2 + 4x = 6...add 4 to both sides of the equation
x^2 + 4x + 4 = 6 + 4
(x + 2)^2 = 10....<== ur constant is 10
x + 2 = (+-)sqrt 10
x = -2 (+ - ) sqrt 10
x = -2 + sqrt 10
x = -2 - sqrt 10