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lianna [129]
2 years ago
10

Solve the formula for the indicated variable. h=vt-5t^2 for v

Mathematics
2 answers:
mezya [45]2 years ago
8 0

we have

h=vt-5t^2

Solve for v

Adds 5t^2 both sides

h+5t^2=vt-5t^2+5t^2

vt=h+5t^2

Divide by t both sides

vt/t=(h+5t^2)/t

v=(h+5t^2)/t

Simplify

v=\frac{h}{t} +5t

therefore

<u>the answer is</u>

<u>v=\frac{h}{t} +5t</u>

lions [1.4K]2 years ago
4 0
v = 5t + h/t {solved for v}
since t is on the right side... vt - 5t^2 = h (solved for t)

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11b-12&lt;-100
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ok wait which symbol? this (<)?

well it should stay the same since -100 is greater than the 11b-12

LHS=RHS

11b÷11b b must cancell b also do the same on -12. -12÷11 will give u a lesser value compared to -100

prove me wrong

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