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Nat2105 [25]
3 years ago
14

For the Data Set below, calculate the Variance to the nearest hundredth decimal place. (Do not use a coma in your answer) 175 34

9 234 512 638 549 500 611
Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Answer:

The variance of the data is 29966.3.

Step-by-step explanation:

The given data set is

175, 349, 234, 512, 638, 549, 500, 611

We need to find the variance to the nearest hundredth decimal place.

Mean of the data

Mean=\dfrac{\sum x}{n}

where, n is number of observation.

Mean=\dfrac{3568}{8}=446

The mean of the data is 446.

Variance=\dfrac{\sum (x-mean)^2}{n-1}

Variance=\dfrac{(175-446)^2+(349-446)^2+(234-446)^2+(512-446)^2+(638-446)^2+(549-446)^2+(500-446)^2+(611-446)^2}{8-1}

Variance=\dfrac{209764}{7}

Variance=29966.2857

Variance\approx 29966.3

Therefore, the variance of the data is 29966.3.

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