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o-na [289]
3 years ago
14

What is the square root of 69

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0
8
is the answer because8 times 8 equal 69
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What is the perimeter of quadrilateral ABCD?
alex41 [277]

Answer:

Perimeter of quadrilateral ABCD will be  104

Step-by-step explanation:

Given quadrilateral A'B'C'D' is a reflection of quadrilateral ABCD over the line m.

So, all the corresponding sides of both the quadrilateral should be equal.

Also, we can see from the diagram that A'D'=32,\ A'B'=22,\ BC=20,\ and\ CD=30

As both image are reflection of same scale we can add corresponding sides.

So, the perimeter of ABCD will be

AB+BC+CD+DA

And we have AB=A'B'\ and\ AD=A'D'

Now, perimeter of  ABCD will be 22+20+30+32

Perimeter of quadrilateral ABCD is 104

5 0
3 years ago
There were 10 fish in a bowl 3 drownded and 4 died how many fish were left
Debora [2.8K]
There would be 3 left but fish can't drown so there's 6 left Hope I helped!
4 0
3 years ago
Read 2 more answers
Mrs. Jacobson wants to order toy instruments to give as prizes to her music students. The table shows the prices for various ord
Leona [35]
First let as solve all unit pirce
whistles 21.25 / 25 = $ 0.85 per unit
36 / 50 = $ 0.72 per unit
60 / 80 = $ 0.75 per unit
kazoos
10 / 25 = $ 0.4 per unit
18.50 / 50 = $ 0.37 per unit
27.20 / 80 = $ 0.34 per unit
a.) $ 0.85 - $ 0.72 = $ 0.13
b.) 10 / 25 = $ 0.4 per unit
c.) he must order 80 kazoos she should
order
7 0
2 years ago
Read 2 more answers
The graph of a quadratic function contains the points
masya89 [10]

Answer:

Shawn is correct.

Step-by-step explanation:

Let the quadratic function is g(x) = a(x - h)² + k

Here (h, k) is the vertex of the parabola.

Since this parabola passes through (0, 0), (1, 9) and (-1, 9), axis of symmetry is x = 0 and the vertex is (0, 0).

Therefore, equation of the parabola will be,

g(x) = a(x - 0)²+ 0

g(x) = ax²

for a point (1, 9) which lies on the graph,

9 = a(1)²

a = 9

g(x) = 9x² (here a > 1)

Therefore, f(x) is vertically stretched by a factor of 9 to form g(x).

Shawn is correct.

3 0
3 years ago
the first term of an arithmetic sequence is 2 and the sum of the first 15 terms is 292.5. Find the common difference
adelina 88 [10]

Given:

First term of an arithmetic sequence is 2.

Sum of first 15 terms = 292.5

To find:

The common difference.

Solution:

We have,

First term: a=2

Sum of first 15 terms: S_{15}=292.5

The formula of sum of first n terms of an AP is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Where, a is first term and d is common difference.

Putting S_{15}=292.5, n=15 and a=2 in the above formula, we get

292.5=\dfrac{15}{2}[2(2)+(15-1)d]

292.5=\dfrac{15}{2}[4+14d]

292.5=15[2+7d]

Divide both sides by 15.

\dfrac{292.5}{15}=2+7d

19.5=2+7d

19.5-2=7d

17.5=7d

Dividing both sides by 7, we get

\dfrac{17.5}{7}=d

2.5=d

Therefore, the common difference is 2.5.

8 0
3 years ago
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