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Ilya [14]
3 years ago
14

Factor the GCF: 15a+25b

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0
The number that goes into 15 and 25 is 5. So after you factor this it would be 5(3a+5b). 
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5+2b-2 <br> =( )b+( )<br> please i need help!!!!
strojnjashka [21]

Answer:

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Step-by-step explanation: sorry im stuck too :(

4 0
3 years ago
Solve the linear system by substitution 3c-2y=16<br> 5x+y=18
andrew11 [14]
It's x or c?
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6 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
What is the volume of a rectangular prism if the length Is 9 the width is 2 and the height is 3
Bas_tet [7]
V = length×width ×height

V = 9 × 2 × 3

V = 54 units cubed
3 0
4 years ago
Rearrange a (q-c)=d to make q the subject
Andrej [43]
To rearrange you must first simplify
aq-ac=d  
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
3 0
3 years ago
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