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postnew [5]
2 years ago
12

Do the points P (-1, 6), Q (3, 7) and R (3, -5) form a right triangle? ( show your work )

Mathematics
1 answer:
Molodets [167]2 years ago
5 0

Step-by-step explanation:

best I could, hopefully this helps

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%7D%20" id="TexFormula1" title=" \sqrt[3]{216} " alt=" \sqrt[3]{216} "
AleksAgata [21]

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8 0
2 years ago
Simplify.<br><br> 1/cosθ + tan^2θ/cosθ<br><br> • 1 + sinθ<br> • sec^3θ<br> • 1<br> • cos^3θ
olchik [2.2K]

Answer:

I'm guessing the answer is sec³θ

Step-by-step explanation:

I tried this problem and I got 1/cos³θ and clicked cos³θ, but that answer was incorrect. In my lesson, there were the options:

1. sec³θ

2. cos³θ

3.  secθ

I didn't have options 1 + sinθ or 1 as answers. If sec³θ is not the correct answer, please correct me.

8 0
2 years ago
List down 5 values of x that makes it TRUE to the equation x - 5 &lt; 35
Molodets [167]

Answer:

5,4,3,2,1

Step-by-step explanation:

4 0
3 years ago
Please help!!
Soloha48 [4]

Step-by-step explanation:

Given points are:

(-1,\:3)=(x_1,\: y_1) \:\&\:(1, \:7)=(x_2,\:y_2)

Equation of line in two point form is given as:

\frac{y-y_1 }{y_1 - y_2}  =  \frac{x-x_1 }{x_1 - x_2} \\  \\  \therefore \:  \frac{y - 3}{3 - 7}  =  \frac{x - ( - 1)}{ - 1 - 1}  \\  \\ \therefore \:  \frac{y - 3}{ - 4}  =  \frac{x  + 1}{ - 2}  \\  \\ \therefore \:  \frac{y - 3}{ 2}  =  \frac{x  + 1}{ 1}  \\  \\ \huge \purple{ \boxed{\therefore \:y - 3 = 2(x + 1)}} \\ this \: is \: the \: equation \: of \: line \: in \:  \\ point - slope \: form.\\simplifying \: it \: further \: we \: find: \\  y - 3 = 2x + 2 \\  \\ \therefore \:y = 2x + 2 + 3 \\  \\  \huge \red{ \boxed{\therefore \:y = 2x + 5}} \\ this \: is \: the \: equation \: of \: line \: in \:  \\  slope - intercept \: form.

3 0
2 years ago
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