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3 years ago

-7x-8y=-19 slope int

Mathematics

1 answer:

Drupady [299]3 years ago

4 0

-8y= 7x-19 (add 7x to both sides)
y= 7x/-8 +19/8 (divide -8 from both sides)

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What is 1928912 times 192 divided by 182 times 9 plus 4 - 12378923789 times -52?

qaws [65]

(1928912×192) ÷ (182×9) + 4- (12378923789×-52)

= 6.437042e11

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3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

Step-by-step explanation:

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

Hint: sin is only positive in Quadrants I and II

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

Hint: sin and cos are only opposite signs in Quadrants II and IV

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

The sum of the squares of two consecutive even integers is 452. find the integers.

Novay_Z [31]

Let me know if you have any questions :-)

7 0

3 years ago

A triangle pattern is shown below.

iren [92.7K]

Answer:

A) P = 6n + 8

Step-by-step explanation:

Given:

Perimeter of the 1 triangle = 24

Perimeter of the 2 triangle = 30

Perimeter of the 3 triangle = 36

Let's check with option A.

P = 6n + 18, where "n" is the number in the figure.

Plug in n = 1, we get

P = 6(1) + 18

= 6 +18

P = 25 True.

Plug in n =2, we get

P = 6(2) + 18

= 12 +18

P = 30 True.

Plug in n =3, we get

P = 6(3) + 18

P = 18 + 18

P = 36, true.

Therefore, the answer is A. P = 6n + 18

Thank you.

6 0

3 years ago

Dy/dx = (sin x)/y , y(0) = 2

skad [1K]

Start with

$\dfrac{dy}{dx}=\dfrac{\sin(x)}{y}$

Separate the variables:

$y\;dy = \sin(x)\;dx$

Integrate both parts:

$\displaystyle \int y\;dy = \int\sin(x)\;dx$

Which implies

$\dfrac{y^2}{2} = -\cos(x)+c$

Solving for y:

$y = \sqrt{-2\cos(x)+c}$

Fix the additive constant imposing the condition:

$y(0) = \sqrt{-2+c}=2 \iff -2+c=4 \iff c=6$

So, the solution is

$y(x) = \sqrt{-2\cos(x)+6}$

5 0

3 years ago